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Airregulationsrkbalipdf 📢





 
 
 
 
 
 
 

Airregulationsrkbalipdf

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Your question has already been answered in in the forum post linked below, but this thread may be helpful to others who have the same question.

Many thanks.

A:

Use
echo -n

instead of
echo -n > file

and make sure that the permissions of the output file are set to “drwxrwxr-x”
The -n option tells it to echo without a newline. The -1 tells it to read from stdin

Q:

How to get the second element in a list that is longer than the other elements in a list?

I’m making an app that creates a timetable and I have a problem when the user starts inputting the times.
I have an empty list called tst_list, and when the user taps the button in the adding timetable textview, it adds a string to tst_list.
If the user deletes the first string of the list, the programme should start adding the next string of the list to the list.
When the user starts inputting the times with their phone, the programme clears the textview so they cannot type again. The programme then tries to append the user’s string to the list again and then it adds the first string again.
Here is my code.
TextView t = (TextView) findViewById(R.id.add_timetable);
t.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
t.setText(“”);
String value = v.getText().toString();
tst_list.add(value);
}
});

When I get the value from the textview, it’s just the first string in the list and I want to make the code so it gets the second element in the list.

A:

If you use List#contains(Object o) or List#get(int index) methods you will get what you want.
list.contains(val)
// Returns true if and only if this list contains the specified element. More
// formally, returns true if and only

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