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Finding the mass-energy of an electron based on the mass-energy of a gram of H2O

I’m having some issues understanding how to calculate the mass-energy of an electron with these two equations. These equations are from a textbook, and I’m not too familiar with the equation or concept.
I thought the electron’s mass was positive, so I would think the mass-energy of the electron would be the mass-energy of a gram of hydrogen, which is $1.00854\cdot10^{ -27}$ kg-molecule$^\text{ -1}$. However, it is simply $3.011\cdot10^{ -35}$ kg.
Is my understanding of the equation wrong? Thanks!

A:

What you must do is assume the electron mass is a unit box with a negative charge.
This is the math you must do:
$$E_0 = \sum\limits_a \rho_a v_a^2\tag{1}$$
$$m = \sum\limits_a \rho_a$$
$$E_0 = m + m\frac{1}{2}\frac{1}{\sum\limits_a \rho_a}$$
$$E_0 = m+\frac{m}{2}\frac{1}{\rho_\text{H}}$$
$$E_0 = \frac{m}{2}\frac{1}{\rho_\text{H}} + 1.00854\cdot10^{ -27} \frac{kg^2 m^2}{kg^2m^2} = 1.00854\cdot10^{ -27} + \frac{1.00854\cdot10^{ -27}}{2m} = 3.011\cdot10^{ -35}\tag{2}$$
The first term of $1.00854\cdot10^{ -27}$ is the mass of the electron per mole and the second term is the mass of the electron per gram.
So you are right about the mass of the electron.
You are wrong when you say the electron
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