The King Of Fighters 2002: Unlimited Match [Steam] ((INSTALL))

The King Of Fighters 2002: Unlimited Match [Steam]

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By N3XN there are currently 33 users on this Steam page. Updated on 10.12.2018 11.56 (Edited) – Watched 31 users watch. Kings of Fighters 2002 Unlimited Match – Playstation 4. The King of Fighters 2002: Unlimited Match PS4 Video Game. KOF 2002 UM was released in 2000, and was the first game in the series released for the PSX. In 2002, the game was retitled KOF 2002: Unlimited Match.Q:

Does anyone know of an elegant way to multiply the content of two lists?

Say I have the following lists:
list1 = {{1, 2}, {3, 4}};
list2 = {{5}, {5}};

Assuming that a and b are known constants, and I want list1 * list2 to give the result
{{a, 2*b}, {3*b}, {5, 5*a}}

I could do:
list3 = {{1, 2*b}, {3, 3*b}, {5, 5*a}};
Cases[list3, {_, _, _}]

However, it seems like there should be a more elegant way to do this. Any ideas?

A:

list1 = {{1, 2}, {3, 4}};
list2 = {{5}, {5}};

(* list3 = {{a, 2 b}, {3 a}, {5, 5 a}} *)

list3 = {list1, list2} //Transpose // Apply[Times]

(* {{a, 2 b}, {3 a}, {5, 5 a}} *)

Or one can use a pattern match:
{Plus @@ #1, _, Plus @@ #2} & @@@ list1*list2 // Chop

{{a, 2 b}, {3 a}, {5, 5 a}}

A:

I would not use Transpose but use only apply:
apply[times_] := Module[{res, t}, res = times t; res /;
Head[res] === Times && Length[res] == 2 Length[t]]

mylist = {{1, 2}, {3, 4}};

apply[times] @@ list1*list2
(* {a, 2 b, 3 a, 5, 5 a} *)
c6a93da74d

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