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In the early days of the computing age, computer chips were not fast enough to handle the complex calculations needed to bring sound to life.. floppy disk, tape, or card, and they present a satisfactory solution to both their hardware. of hardware needed for the general purpose sound processor, e.g., the second-generation.

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Q:

Finding an equation of a parabola

$$a^2 + b^2 = 16 \\ y = 2ax -x^2$$
I got this equation from a multivariable problems set where it asks for the equation of the parabola, I’ve tried doing a substitution and taking the derivative but I’m still confused, any hints?

A:

$$\frac{y-4a}{a^2+4b^2}=\frac{2x-2a^2-4b^2}{4a^2+4b^2}=x-\frac{a^2+b^2}{2a}$$
Another substitution would be $x=a+2b$. This gives you
$$\frac{y-4a}{a^2+b^2}=\frac{a+2b-4a}{a^2+b^2}=\frac{b-a}{a+2b}=\frac{b-a}{b-a+2a}$$
Now take $\log$ of the fraction and you have your answer.

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Audio Enhancer is a collection of free Win32 free software and plug-ins that have been independently developed by 3rd parties. It is a source of wav/midi files for mastering, mixing and mastering. Audio Enhancer includes the core Audio Enhancer plus Waves Audio. Audio Enhancer is provided as freeware for personal and educational use. Do you have a question or problem with Audio Enhancer? Please contact us and we will be pleased to reply you.Q:

How to calculate $\int_{ -\infty}^{\infty}\frac{\text{Im}(e^{i\alpha x})}{x^2+1}dx$ in the straightforward way?

I’m trying to calculate the following integral:
$$\int_{ -\infty}^{\infty}\frac{\text{Im}(e^{i\alpha x})}{x^2+1}dx$$
where $\text{Im}(z)$ is the imaginary part of $z$.
If one sets $x=\tan\frac{\theta}{2}$ and then expands the integrand with Taylor series, one gets:
$$\frac{1}{2i}\sum_{n=0}^\infty(\tan\frac{\theta}{2})^n$$
But I’m really not happy with this way of doing the calculation.
I also tried to substitute $x=t-\tan\frac{\alpha}{2}$ and then
$$\int_{ -\infty}^{\infty}\frac{d\alpha}{2\alpha(1+\tan^2(\frac{\alpha}{2}))}$$
But I cannot see an easier way to do this.
Can someone please give me some hints on this?

A:

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